Digit Problem – Problem 2

\[ \frac{1}{3 – i} \times \frac{3 + i}{3 + i} = \frac{3 + i}{9 + 3i – 3i + 1} = \frac{3 + i}{9 + 1} = \frac{3 + i}{10} = 0.3 + 0.1i \leftarrow \text{answer} \]