Daniel is twice as old as Jimmy. Terry is one year younger than Daniel. If the sum of their age is 44. How old is Daniel?
$\text{Let:}$
$\text{Daneil = D}$
$\text{Jimmy = J}$
$\text{Terry = T}$
\[
D = 2J; J = \frac{D}{2}
\]
\[
T = D – 1
\]
\[
D + J + T = 44
\]
\[
D + (\frac{D}{2}) + (D – 1) = 44
\]
\[
D = 18 \leftarrow \text{answer}
\]