Given the triangulation figure shown below, which has already been adjusted. The length of the baseline AB is 4346.50m. Using the route with BC as the common side, compute the length of line CD. 2914.70 4135.84 6943.22 5634.92 Click to Show/Hide Solution \[ \frac{BC}{\sin 71^{\circ}} = \frac{AB}{\sin 45^{\circ}} \] \[ \frac{BC}{\sin 71^{\circ}} = \frac{4346.50m.}{\sin 45^{\circ}} \] \[ BC = \frac{4346.50m. (\sin 71^{\circ})}{\sin 45^{\circ}} \] \[ BC = 5811.99m. \] \[ \frac{CD}{\sin 20^{\circ}} = \frac{BC}{\sin 43^{\circ}} \] \[ \frac{CD}{\sin 20^{\circ}} = \frac{5811.99m.}{\sin 43^{\circ}} \] \[ BC = \frac{5811.99m. (\sin 20^{\circ})}{\sin 43^{\circ}} \] \[ BC = 2914.70m. \leftarrow \text{answer} \]