Two flies from the same point are flying away from each other in different direction and the angle between them is 84.1°. Fly A is moving at a speed of $12.2 \frac{m.}{min.}$ while the other fly at $17.4 \frac{m.}{min.}$. How many meters are they apart after 2.4 minutes?
- 68.68 m.
- 58.58 m.
- 48.48 m.
- 38.38 m.
\[
\text{Distance traveled by Fly A after 2.4 minutes} = D_A = V_A \times T = 12.2 \frac{m.}{min.} \times 2.4 min. = 29.28 m.
\]
\[
\text{Distance traveled by Fly B after 2.4 minutes} = D_B = V_B \times T = 17.4 \frac{m.}{min.} \times 2.4 min. = 41.76 m.
\]
\[
c^2 = a^2 + b^2 – 2ab \cos \theta
\]
\[
c^2 = 29.28^2 + 41.76^2 – 2(29.28)(41.76) \cos 84.1^\circ
\]
\[
c = 48.48 m. \leftarrow \text{answer}
\]
