A triangular lot was surveyed with a steel tape and found to have the following side lengths, 23.56m., 38.54m., and 33.40m. Determine the angle opposite the 38.54m. side. 71.24° 83.24° 56.27° 48.17° Click to Show/Hide Solution \[ c^2 = a^2 + b^2 - 2ab \cos \theta \] \[ 38.54^2 = 33.40^2 + 23.56^2 - 2(33.40)(23.56) \cos \theta \] \[ \theta = 83.24^\circ \leftarrow \text{aswer} \]