A line measures 6422.46m. at an average elevation of 400m. If the average radius of curvature of vicinity is 6400000m., determine the equivalent mean sea level length.
6422.06m.
6421.91m.
6421.86m.
6422.24m.
\[
L’ = L \times C_f
\]
\[
C_f = 1 – \frac{h}{R}
\]
\[
C_f = 1 – \frac{400m.}{6400000m.}
\]
\[
C_f = 0.9999375
\]
\[
L’ = 6422.46m. \times 0.9999375
\]
\[
L’ = 6422.06m. \leftarrow \text{answer}
\]