What is the sum of the first 25 terms of the progression 5, 8, 11, 14, . . . . . Click to Show/Hide Solution \[ S_n = \frac{n}{2}[2a_1 + (n - 1) d] \] \[ S_{25} = \frac{25}{2}[2(5) + (25 - 1) (3)] \] \[ S_{25} = 1025 \leftarrow \text{answer} \]
