What is the sum of the first 50 terms of the progression 3, 5, 7, 9, . . . . . Click to Show/Hide Solution \[ S_n = \frac{n}{2}[2a_1 + (n - 1) d] \] \[ S_{50} = \frac{50}{2}[2(3) + (50 - 1) (2)] \] \[ S_{50} = 2600 \leftarrow \text{answer} \]
